Answer
(a).$n(t)=391.9$
(b).$n(t)=73.04$
Work Step by Step
$n(t)=n_0\times e^{rt}$. Whereas,$n(t)$ is population at time $t$, $n_0$ is Initial size of the population, $r$ is relative rate of growth, and $t$ is time.
(a).$n_0=22$, $r=0.12$, $t=24$.
$n(t)=22\times e^{0.12 \times 24}=391.9$
(b).$n_0=22$, $r=0.05$, $t=24$.
$n(t)=22\times e^{0.05 \times 24}=73.04$
