## College Algebra 7th Edition

(a) $x=10$ (b) $x=5$
(a) We are given: $\log_{x}1000=3$ This means: $x^{3}=1000$ $x=(1000)^{1/3}=10$ (b) We are given: $\log_{x}25=2$ This means: $x^{2}=25$ $x=\pm\sqrt{25}=\pm 5$ $x=5$ (a log base can't be negative)