College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.3 - Logarithmic Functions - 4.3 Exercises - Page 388: 41


(a) $x=-1$ (b) $x=\frac{1}{1000}$

Work Step by Step

(a) $x=\log_{2}(\frac{1}{2})=\log_{2}(2^{-1})=-1$ (b) We are given: $\log_{10^{X}}=-3$ This means: $10^{-3}=x$ $x=10^{-3}=\frac{1}{1000}$
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