## College Algebra 7th Edition

(a) $x=\dfrac{1}{9}$ (b) $x=3$
RECALL: $\log_b{x}=y \longrightarrow b^x=y$ Use the rule above to obtain: (a) $\begin{array}{ccc} &3^{-2}&=&x \\&\dfrac{1}{3^2}&=&x \\&\dfrac{1}{9}&=&x \end{array}$ (b) $\begin{array}{ccc} &5^x&=&125 \\&5^x&=&5^3 \end{array}$ Use the rule $a^m=a^n \longrightarrow m=n$ to obtain: $x=3$