College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 3, Polynomial and Rational Functions - Section 3.4 - Real Zeros of Polynomials - 3.4 Exercises - Page 320: 34


$P(x)=(2x-3)(x-1)(x+1)$ zeros: $\displaystyle \pm 1, \frac{3}{2}$

Work Step by Step

Factor in pairs: $2x^{3}-3x^{2}-2x+3=x^{2}(2x-3)-(2x-3)=(2x-3)(x^{2}-1)$ ... recognize a difference of squares. $P(x)=(2x-3)(x-1)(x+1)$ zeros: $\displaystyle \pm 1, \frac{3}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.