Answer
Quotient $Q(x)=2x^2-11x+58$
Remainder $R(x)=-294$
Work Step by Step
$\frac{2x^3-x^2+3x-4}{x+5}$, dividing using synthetic division:
$\begin{array}{lllll}
\underline{-5}| &2& -1 & 3 & -4 & \\
& & -10&55 & -290 & \\
\hline & & & & \\
&2& -11 & 58 & -294 &
\end{array}$
$(2x^3-x^{2}+3x-4)\div(x+5)=2x^2-11x+58 $ $-\frac{294}{x+5}$.
thus, Quotient is $Q(x)=2x^2-11x+58$ and remainder is $R(x)=-294$
