Answer
Quotient $Q(x)=x-2$
Remainder $R(x)=-4$.
Work Step by Step
$\frac{x^2-5x+2}{x-3}$, dividing using synthetic division:
$\begin{array}{lllll}
\underline{3}| & 1 & -5 & 2 & \\
& & 3 & -6 & \\
\hline & & & & \\
& 1 & -2 & -4 &
\end{array}$
$(x^{2}-5x+2)\div(x-3)=x-2 $ $-\frac{4}{x-3}$.
thus, Quotient is $Q(x)=x-2$ and remainder is $R(x)=-4$.
