## College Algebra 7th Edition

$g(x)=-(x-2)^2+1=-x^{2}+4x-3$
We obtain $g(x)$ by reflecting $f(x)=x^2$ about the $x$-axis and shifting right 2 units and up 1 unit, i.e. $y=-f(x-2)+1$ $g(x)=-(x-2)^2+1=-(x^2-4x+4)+1=-x^{2}+4x-3$