## College Algebra 7th Edition

$y=2(x-3)^2-2$
We begin with: $f(x)=x^2$ We are told to stretch vertically by a factor of 2, shift down 2 units, and shift 3 units right. This means: $y=2f(x-3)-2$. Thus we get: $y=2(x-3)^2-2$