## College Algebra 7th Edition

Published by Brooks Cole

# Chapter 2, Functions - Section 2.6 - Transformations of Functions - 2.6 Exercises: 61

#### Answer

$y=2(x-3)^2-2$

#### Work Step by Step

We begin with: $f(x)=x^2$ We are told to stretch vertically by a factor of 2, shift down 2 units, and shift 3 units right. This means: $y=2f(x-3)-2$. Thus we get: $y=2(x-3)^2-2$

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