## College Algebra 7th Edition

$f^{-1}(1)=0$ $f^{-1}(3)=4$
We see from the graph that $f(0)=1$. This means that $f^{-1}(1)=0$ ($x$ and $y$ get switched). Similarly, we see from the graph that $f(4)=3$ and therefore $f^{-1}(3)=4$.