#### Answer

(a) yes, one-to-one
(b) not one-to-one

#### Work Step by Step

(a) The function $f(x)=x^3+1$ is one-to-one. It passes the horizontal line test (it is a shifted cubic function, which is odd). Since the equation only contains a cube and addition, every unique $x$ value will have a unique $y$ value, ensuring that the function is one-to-one.
(b) The function $g(x)=|x+1|$ is not one-to-one because we can find two $x$ values that will produce the same $y$ value. For example:
$g(0)=|0+1|=|1|=1$
$g(-2)=|-2+1|=|-1|=1$
Thus the function is not one-to-one.