College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Chapter 2 Review - Exercises - Page 268: 52

Answer

Net change: 35 Average rate of change: $\frac{7}{4}$

Work Step by Step

We find the net change from $x=10$ to $x=30$: $g(30)-g(10)=30--5=35$ Next we find the average rate of change for this interval: $\frac{g(30)-g(10)}{30-10}=\frac{35}{20}=\frac{7}{4}$
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