College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Chapter 2 Review - Exercises - Page 268: 39



Work Step by Step

We are given: $x+y^{2}=14$ We solve for $y$: $y^{2}=14-x$ $y=\pm\sqrt{14-x}$ Since $y$ can have two values for the same $x$ value (the positive and negative), $y$ does not describe a function of $x$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.