College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Chapter 2 Review - Exercises - Page 268: 22


the domain is: $\{x|x\neq-4\}$

Work Step by Step

We are given: $f(x)= \frac{\sqrt[3]{2x+1}}{\sqrt[3]{2x}+2}$ We know that the denominator can not be 0: $\sqrt[3]{2x}+2\neq 0$ $\sqrt[3]{2x}\neq-2$ $2x\neq(-2)^3$ $2x\neq-8$ $x\neq-4$ Therefore, the domain is: $\{x|x\neq-4\}$.
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