#### Answer

$y=3x-3$

#### Work Step by Step

RECALL:
(1) The slope-intercept form of a line's equation is $y=mx+b$ where m = slope and b = y-intercept.
(2) The slope of a line can be found using the formula $m=\dfrac{y_2-y_1}{x_2-x_1}$ where $(x_1, y_1)$ and $(x_2, y_2)$ are points on the line.
The x-intercept is $1$ so the point $(1, 0)$ is on the line.
The y-intercept is $-3$, so $b=-3$.
Thus, the tentative equation of the line is:
$y=mx+(-3)
\\y=mx-3$
To find the value of $b$, substitute the x and y coordinates of the point $(1, 0)$ into the tentative equation above to obtain:
$y=mx-3
\\0=m(1) - 3
\\0=m-3
\\0+3=m
\\3=m$
Therefore, the equation of the line is:
$y=3x-3$