College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Chapter 1 Review - Exercises - Page 169: 9



Work Step by Step

Since the circle passes through the origin, we know that it contains the point $(0,0)$. We can use this fact to find the radius. We are given that the circle has a center of $C=(-5,-1)$, so we have: $r=\sqrt{(0--5)^{2}+(0--1)^{2}}=\sqrt{(0+5)^{2}+(0+1)^{2}}=\sqrt{25+1}=\sqrt{26}$ So the equation is: $(x+5)^{2}+(y+1)^{2}=(\sqrt{26})^2=26$
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