#### Answer

$(x-2)^{2}+(y+5)^{2}=2$

#### Work Step by Step

We use the circle formula with center $(2,\ -5)$ and radius $\sqrt{2}$:
$(x-2)^{2}+(y--5)^{2}=(\sqrt{2})^{2}$
$(x-2)^{2}+(y+5)^{2}=2$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$(x-2)^{2}+(y+5)^{2}=2$

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