College Algebra 7th Edition

$(x-2)^{2}+(y+5)^{2}=2$
We use the circle formula with center $(2,\ -5)$ and radius $\sqrt{2}$: $(x-2)^{2}+(y--5)^{2}=(\sqrt{2})^{2}$ $(x-2)^{2}+(y+5)^{2}=2$