Answer
$(x-2)^{2}+(y+5)^{2}=2$
Work Step by Step
We use the circle formula with center $(2,\ -5)$ and radius $\sqrt{2}$:
$(x-2)^{2}+(y--5)^{2}=(\sqrt{2})^{2}$
$(x-2)^{2}+(y+5)^{2}=2$
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