College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Summary, Review, and Test - Review Exercises - Page 91: 98

Answer

$(x^2+4)(x+2)(x-2)$

Work Step by Step

Use the formula $a^2-b^2=(a+b)(a-b)$. Then use it again for the second set of parentheses to factor completely. $x^4-16$ $(x^2+4)(x^2-4)$ $(x^2+4)(x+2)(x-2)$
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