College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Summary, Review, and Test - Review Exercises - Page 91: 96

Answer

$(x-3)^2(x+3)$

Work Step by Step

Place the four terms into two groups. Then pull out the greatest common factor of each. Then factor $x^2-9$ using $A^2-B^2=(A+B)(A-B)$. Then simplify further. $x^3-3x^2-9x+27$ $(x^3-3x^2)-(9x-27)$ $x^2(x-3)-9(x-3)$ $(x-3)(x^2-9)$ $(x-3)(x-3)(x+3)$ $(x-3)^2(x+3)$
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