College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Summary, Review, and Test - Review Exercises - Page 91: 83

Answer

$24x^3y^2+x^2y-12x^2+4$; degree is $5$

Work Step by Step

Start by breaking down the parentheses. Then combine like terms to simplify. The degree is the combined powers of the highest exponents if there are two variables. $(13x^3y^2-5x^2y-9x^2)-(-11x^3y^2-6x^2y+3x^2-4)$ $13x^3y^2-5x^2y-9x^2+11x^3y^2+6x^2y-3x^2+4$ $24x^3y^2+x^2y-12x^2+4$
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