Answer
$\frac{16(1+2x)}{\sqrt[4] {x^{3}}}$
Work Step by Step
Factor out $16$ and $x$ at $x^{-\frac{3}{4}}$, the smallest exponent. Then use the formula $a^{-m/n}=\frac{1}{a^{m/n}}=\frac{1}{\sqrt[n] {a^m}}$ to simplify further.
$16x^{-\frac{3}{4}}+32x^{\frac{1}{4}}$
$16x^{-\frac{3}{4}}+2*16*32x^{-\frac{3}{4}}*x^1$
$16x^{-\frac{3}{4}}(1+2x)$
$\frac{16(1+2x)}{\sqrt[4] {x^{3}}}$
