Answer
P=$\frac{4x^2+14x}{x^2+7x+12}$
Work Step by Step
P=2($\frac{x}{x+3}$)+2($\frac{x}{x+4}$)
P=$\frac{2x}{x+3}$+$\frac{2x}{x+4}$
P=$\frac{2x^2+8x}{x^2+7x+12}$+$\frac{2x^2+6x}{x^2+7x+12}$
P=$\frac{4x^2+14x}{x^2+7x+12}$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.6 - Page 88: 84
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