College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.6 - Page 88: 109

Answer

It cubes $x$.

Work Step by Step

It cubes $x$. (Because $\frac{1}{x}+\frac{1}{x^2}+\frac{1}{x^3}=\frac{x^2+x+1}{x^3}$ and $\frac{1}{x^4}+\frac{1}{x^5}+\frac{1}{x^6}=\frac{x^2+x+1}{x^6}$)
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