Answer
Following the format $(x, y)$:
$(-3, -8)$
$(-2, -3)$
$(-1, 0)$
$(0, 1)$
$(1, 0)$
$(2, -3)$
$(3, -8)$
Work Step by Step
Integers from $-3$ to $3$ include the following values for $x$: $-3, -2, -1, 0, 1, 2, 3$. Therefore, we simply need to use these values in the equation provided $(y = 1-x^2)$ to find the values of $y$:
$y = 1 - (-3)^2 = 1 - 9 = -8$
$y = 1 - (-2)^2 = 1 - 4 = -3$
$y = 1 - (-1)^2 = 1 - 1 = 0$
$y = 1 - (0)^2 = 1-0 = 1$
$y = 1 - (1)^2 = 1 - 1 = 0$
$y = 1 - (2)^2 = 1 - 4 = -3$
$y = 1 - (3)^2 = 1 - 9 = -8$
