College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.6 - Page 87: 78


$\frac{1}{y(y+2)}; y \ne 0,-2;$

Work Step by Step

$\frac{y^{-1}- (y+2)^{-1}}{2}$ The given expression can be written as $=\frac{\frac{1}{y}- \frac{1}{y+2}}{2}; y \ne 0,-2;$ Take LCD in the numerator $=\frac{\frac{y+2-y}{y(y+2)}}{2}; y \ne 0,-2;$ $=\frac{\frac{2}{y(y+2)}}{2}; y \ne 0,-2;$ $ =\frac{2}{y(y+2)} \times \frac{1}{2}; y \ne 0,-2;$ Cross out common factor. $= \frac{1}{y(y+2)}; y \ne 0,-2;$
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