College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.6 - Page 87: 61


$\frac{x+1}{3x-1} ; x\ne 0, \frac{1}{3}$

Work Step by Step

$\frac{1+\frac{1}{x}}{3-\frac{1}{x}} = \frac{\frac{x+1}{x}}{\frac{3x-1}{x}} ; x\ne 0, \frac{1}{3}$ $= \frac{x+1}{x} \times \frac{x}{3x-1};x\ne 0, \frac{1}{3}$ $= \frac{x+1}{3x-1} ; x\ne 0, \frac{1}{3}$
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