Answer
$2; x \ne -1, 2;$
Work Step by Step
$ (2 - \frac{6}{x+1})(1+ \frac{3}{x-2})$
Take LCD,
$= ( \frac{2(x+1)-6}{x+1})( \frac{1(x-2)+3}{x-2}); x \ne -1, 2;$
$= ( \frac{2x+2-6}{x+1})( \frac{x-2+3}{x-2}); x \ne -1, 2;$
$= ( \frac{2x-4}{x+1})( \frac{x+1}{x-2}); x \ne -1, 2;$
$= ( \frac{2(x-2)}{x+1})( \frac{x+1}{x-2}); x \ne -1, 2;$
$= \frac{2(x-2)}{x+1} \times \frac{x+1}{x-2}; x \ne -1, 2;$
Divide common factors.
$= 2; x \ne -1, 2;$
