Answer
$\frac{(4x+5)(x+4)}{(x+2)(x-1)} ; x \ne -2,1;$
Work Step by Step
$(4 - \frac{3}{x+2})(1 + \frac{5}{x-1})$
$= (\frac{4(x+2)-3}{x+2})(\frac{x-1+5}{x-1}) ; x \ne -2,1;$
$= (\frac{4x+8-3}{x+2})(\frac{x-1+5}{x-1}) ; x \ne -2,1;$
$= (\frac{4x+5}{x+2})(\frac{x+4}{x-1}) ; x \ne -2,1;$
$= \frac{(4x+5)(x+4)}{(x+2)(x-1)} ; x \ne -2,1;$
