College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3 - Page 49: 94

Answer

$8x^{\frac{5}{12}}$

Work Step by Step

$$\frac{72x^{\frac{3}{4}}}{9x^{\frac{1}{3}}}$$ When two rational expressions with the same base are divided, subtract the exponents. $$=(\frac{72}{9})(x^{(\frac{3}{4} - \frac{1}{3})})$$ When subtracting fractions, you need a common denominator, in this case, 12: $$=8x^{(\frac{9}{12} - \frac{4}{12})}$$ $$=8x^{\frac{5}{12}}$$
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