College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3: 78



Work Step by Step

$$3\sqrt[3]{24} + \sqrt[3]{81}$$ $$=3\sqrt[3]{8\times3} + \sqrt[3]{27\times3}$$ $$=(3\times2)\sqrt[3]{3} +3\sqrt[3]{3}$$ $$=6\sqrt[3]{3} + 3\sqrt[3]{3}$$ $$=(6+3)\sqrt[3]{3}$$ $$=9\sqrt[3]{3}$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.