College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3 - Page 49: 107

Answer

$\sqrt[3]{x^2y}$

Work Step by Step

$$\sqrt[9]{x^6y^3}$$ To convert from a radical expression to an expression with a rational exponent, the exponent becomes the numerator, and the index becomes the denominator: $$=x^\frac{6}{9}y^\frac{3}{9}$$ Simplify all fractions: $$=x^\frac{2}{3}y^\frac{1}{3}$$ Convert back to a radical expression - the numerator becomes the exponent, the denominator becomes the index: $$=\sqrt[3]{x^2y}$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.