College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3: 109



Work Step by Step

$$\sqrt[3]{\sqrt[4]{16}+\sqrt{625}}$$ $$=\sqrt[3]{2+25}$$ $$=\sqrt[3]{27}$$ $$=3$$
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