Answer
The foci are located at
$(0, -\sqrt{39})$ and $(0, \sqrt{39})$
Work Step by Step
Major axis parallel to the $y$-axis, vertical.
$a^{2}=64,$
$a=8$
$b^{2}=25,$
$b=5$
Vertices: $(h, k-a),\quad (h, k+a) $
$(0, -8),\quad (0, 8) $
Foci are $c$ units above and $c$ units below the center,
$c^{2}=a^{2}-b^{2}=64-25=39$
$c=\sqrt{39}$
The foci are located at
$(0, -\sqrt{39})$ and $(0, \sqrt{39})$