Answer
The foci are located at
$(0, -3\sqrt{3})$ and $(0,3\sqrt{3})$
Work Step by Step
Major axis parallel to the $y$-axis, vertical.
$a^{2}=36,$
$a=6$
$b^{2}=9,$
$b=3$
Vertices: $(h, k-a),\quad (h, k+a) $
$(0, -6),\quad (0, 6) $
Foci are $c$ units above and $c$ units below the center,
$c^{2}=a^{2}-b^{2}=36-9=27$
$c=\sqrt{27}=3\sqrt{3}$
The foci are located at
$(0, -3\sqrt{3})$ and $(0,3\sqrt{3})$.
