Answer
Foci:
$(0,1)$ and $(0, -1)$.
Work Step by Step
Write the equation in standard form:
$6x^{2}=30-5y^{2}\qquad/+5y^{2}$
$6x^{2}+5y^{2}=30\qquad/\div 30$
$\displaystyle \frac{x^{2}}{5}+\frac{y^{2}}{6}=1$
Major axis parallel to the $y$-axis, vertical.
$a=\sqrt{6}\approx 2.45$
$b=\sqrt{5}\approx 2.24$
Foci are $c$ units above and $c$ units below the center,
$c^{2}=6-5=1$
$c=1$
Foci:
$(0,1)$ and $(0, -1)$.
