Answer
Foci:
$(-2\sqrt{3},0)$ and $(2\sqrt{3},0)$.
Work Step by Step
Major axis parallel to the x-axis, horizontal
$a^{2}=16$
$a=4$
$b^{2}=4,$
$b=2$
Center: (0,0)
Vertices: $(h-a, k),\quad (h+a, k) $
$(-4, 0),\quad (4, 0) $
Foci are $c$ units right and $c$ units left of center,
where $c^{2}=a^{2}-b^{2}:$
$c^{2}=a^{2}-b^{2}=16-4=12$
$c=\sqrt{12}=2\sqrt{3}$
Foci:
$(-2\sqrt{3},0)$ and $(2\sqrt{3},0)$.
