College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Matrices and Determinants - Exercise Set 6.1 - Page 599: 17

Answer

$\left[\begin{array}{llllll} 1 & -1 & 1 & 1 & | & 3\\ 0 & 1 & -2 & -1 & | & 0\\ 0 & 2 & 1 & 2 & | & 5\\ 0 & 6 & -3 & -1 & | & -9 \end{array}\right]$

Work Step by Step

The elements of the third row will be replaced with $-2(1)+2=0,$ $-2(-1)+0=2,$ $-2(1)+3=1,$ $-2(1)+4=2,$ $-2(3)+11=5$, to become $0\ \ 2\ \ 1\ \ 2\ \ |\ \ 5.$ The elements of the fourth row will be replaced with $-5(1)+5=0,$ $-5(-1)+1=6,$ $-5(1)+2=-3,$ $-5(1)+4=-1,$ $-5(5)+6=-9$, to become $0\ \ 6\ \ -3\ \ -1\ \ |\ \ -9$ so, the resulting matrix is . $\left[\begin{array}{llllll} 1 & -1 & 1 & 1 & | & 3\\ 0 & 1 & -2 & -1 & | & 0\\ 0 & 2 & 1 & 2 & | & 5\\ 0 & 6 & -3 & -1 & | & -9 \end{array}\right]$
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