College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Matrices and Determinants - Exercise Set 6.1 - Page 599: 16

Answer

$\left[\begin{array}{lllll} 1 & -1 & 5 & | & -6\\ 0 & 6 & -16 & | & 28\\ 1 & 3 & 2 & | & 5 \end{array}\right]$

Work Step by Step

The second row elements will be replaced with $1(-3)+3\ =0,$ $-1(-3)+1\ =6,$ $5(-3)+(-1) =-16,$ $| -6(-3)+10=28$ resulting in $\left[\begin{array}{lllll} 1 & -1 & 5 & | & -6\\ 0 & 6 & -16 & | & 28\\ 1 & 3 & 2 & | & 5 \end{array}\right]$
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