College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Matrices and Determinants - Exercise Set 6.1 - Page 599: 15

Answer

$\left[\begin{array}{lllll} 1 & -3 & 2 & | & 0\\ 0 & 10 & -7 & | & 7\\ 2 & -2 & 1 & | & 3 \end{array}\right]$

Work Step by Step

The second row will be replaced ... $\left[\begin{array}{lllll} * & * & * & | & *\\ 1(-3)+3 & -3(-3)+1 & 2(-3)+(-1) & | & 0(-3)+7\\ * & * & * & | & * \end{array}\right]$ resulting in $\left[\begin{array}{lllll} 1 & -3 & 2 & | & 0\\ 0 & 10 & -7 & | & 7\\ 2 & -2 & 1 & | & 3 \end{array}\right]$
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