Answer
The solution set is the region shaded GRAY
Work Step by Step
We will graph the solution region for each inequality.
1. $x^{2}+y^{2}=16$
is a circle , center at (0,0), radius $4$.
Border: solid (inequality : $\leq$ )
Testing (0,0):$\quad 0^{2}+0^{2} \leq 16?$
Yes, shade the region containing (0,0)
2. The function $y=2^{x}$ is exponential, base $> 1$ (rises)
Some points: $(-1,0.5),(0,1),(1,2),(2,4)$
Border: dashed (inequality : $
