Answer
The solution set is the region shaded GRAY
.
Work Step by Step
We will graph the solution region for each inequality.
1. $x^{2}+y^{2}=16$
is a circle , center at (0,0), radius $4$.
The border is a dashed line (inequality : $ 1$ (rises)
Some points: $(-1,0.5),(0,1),(1,2),(2,4)$
Border> solid (inequality : $\geq$ )
Testing (0,0):$\quad 0 \geq 2^{0}?$
No, shade the region not containing (0,0)
The solution set is the region with BOTH shadings.
The solution set is the region shaded GRAY