College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.5 - Page 572: 53

Answer

The solution set is the region shaded GRAY

Work Step by Step

We will graph the solution region for each inequality. 1. $x^{2}+y^{2}=1$ is a circle , center at (0,0), radius 1. The border is a solid line (inequality : $\leq$ ) Testing (0,0):$\quad 0^{2}+0^{2} \leq 1?$ Yes, shade the region containing (0,0) 2. $y-x^{2}=0$ can be rewritten as $y=x^{2}$, which is a parabola, opening up, vertex at (0,0) Additional points : ($\pm 1,1), (\pm 2,4)$ Border: dashed (inequality : $>$ ) Test (0,1) (not the origin as it lies on the curve), $1-0^{2}>0?$ Yes, shade the region containing (0,1) The solution set is the region with BOTH shadings. The solution set is the region shaded GRAY
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.