Answer
The solution set is the region shaded GRAY
Work Step by Step
We will graph the solution region for each inequality.
1. $x^{2}+y^{2}=1$
is a circle , center at (0,0), radius 1.
The border is a solid line (inequality : $\leq$ )
Testing (0,0):$\quad 0^{2}+0^{2} \leq 1?$
Yes, shade the region containing (0,0)
2. $y-x^{2}=0$ can be rewritten as
$y=x^{2}$, which is a parabola, opening up, vertex at (0,0)
Additional points : ($\pm 1,1), (\pm 2,4)$
Border: dashed (inequality : $>$ )
Test (0,1) (not the origin as it lies on the curve),
$1-0^{2}>0?$
Yes, shade the region containing (0,1)
The solution set is the region with BOTH shadings.
The solution set is the region shaded GRAY