## College Algebra (6th Edition)

We will graph the solution region for each inequality. 1. (red) $x^{2}+y^{2}=4^{2}$ is a circle centered at the origin, radius = 4. Border: solid line ( sign is $\leq )$, Testing $(0,0):\quad 0 + 0^{2} \leq 16\quad?$ Yes, shade the region containing $(0,0)$ 2 (blue) To graph a line, we need two points...unless we know it is vertical or horizontal. $x+y=2 \quad$dashed line ( sign is $> )$, x-intercept:$\quad x+0=2\quad$ point: ($2,0)$ y-intercept:$\quad 0+y=2\quad$ point: ($0,2)$ Testing $(0,0)$:$\quad 0+0 \geq 2 \quad ?$ No, shade the region not containing (0,0) The solution set is the region with BOTH shadings. The solution set is the region shaded GRAY