College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.5 - Page 571: 26

Answer

please see image .
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Work Step by Step

1. The inequality sign is $\geq $, so we draw a solid border 2. The border, $y=\log_{3}(\mathrm{x}-1)$ is a logarithmic function, base $3 > 1,$ It is obtained from $\log_{3}x$ by shifting left by one unit. The function is defined only for $x>1.$ This means that its vertical asymptote, $x=1$ will not be included in the solution, and will be a border. We graph it with a dashed line (not included) and will shade only to the right of the asymptote. Plot some points (see table) and join with a smooth (solid) curve 3. We ca$\mathrm{n}^{\prime}$t test the point $(0,0)$, as the inequality defined only for $x>1.$ We test (10,0) $ 0 \geq \log_{3}(10-1)\quad ?$ $0 \geq \log_{3}9\quad ?$ $0 \geq 2\quad ?$ No. 4. Shade the region that the point (10,0) does not belong to. Also, apply the observation about the vertical asymptote
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