## College Algebra (6th Edition)

1. The inequality sign is $\geq$, so we draw a solid border 2. The border, $y=\log_{2}(\mathrm{x}+1)$ is a logarithmic function, base $2 > 1,$ It is obtained from $\log_{2}x$ by shifting left by one unit. The function is defined only for $x>-1.$ This means that its vertical asymptote, $x=-1$ will not be included in the solution, and will be a border. We graph it with a dashed line (not included). Plot some points (see table) and join with a smooth (solid) curve 3. We can't test the point $(0,0)$, as it lies on the border curve. We test (1,0) $0 \geq \log_{2}(1+1)\quad ?$ $0 \geq \log_{2}2\quad ?$ $0 \geq 1\quad ?$ No. 4. Shade the region that the point (1,0) does not belong to. Also, apply the observation about the vertical asymptote (we shade the region to the right of the asymptote)