#### Answer

please see image
.

#### Work Step by Step

1. The inequality sign is $< $, so we draw a dashed border
2. The border, $(x-2)^{2}+(y+1)=3^{2}$,
is a circle, centered at $(2,-1)$, radius=$3$
3. Test the point $(2,-1)$, the center:
$(2-2)^{2}+(-1+1) ^2<9\quad ?$
$0 < 9\quad ?$
Yes.
4. Shade the region that the center, $(2,-1)$, belongs to
(the region inside the circle)