#### Answer

please see image
.

#### Work Step by Step

1. The inequality sign is $< $, so we draw a dashed border
2. The border, $(x+2)^{2}+(y-1)^{2}=4^{2}$,
is a circle, centered at $(-2,1)$, radius=$4$
3. Test the point $(-2,1)$, the center:
$(-2+2)^{2}+(1-1)^{2} < 16\quad ?$
$0 < 16\quad ?$
Yes.
4. Shade the region that the center, $(-2,1)$, belongs to
(the region inside the circle)