## College Algebra (6th Edition)

1. The inequality sign is $<$, so we draw a dashed border 2. The border, $(x+2)^{2}+(y-1)^{2}=4^{2}$, is a circle, centered at $(-2,1)$, radius=$4$ 3. Test the point $(-2,1)$, the center: $(-2+2)^{2}+(1-1)^{2} < 16\quad ?$ $0 < 16\quad ?$ Yes. 4. Shade the region that the center, $(-2,1)$, belongs to (the region inside the circle)