College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.1 - Page 527: 48

Answer

(8, -1)

Work Step by Step

Set the denominators equal to each other $\frac{x-y}{3} = \frac{x + y}{2} - \frac{1}{2}$ $\frac{2(x-y)}{6} = \frac{3(x + y)}{6} - \frac{3}{6}$ 2(x-y) = 3(x + y) - 3 2x - 2y = 3x + 3y - 3 -x = 5y - 3 x = -5y + 3 $\frac{x+2}{2} - 4 = \frac{y+4}{3}$ $\frac{3(x+2)}{6} - \frac{24}{6} = \frac{2(y+4)}{6}$ 3(x+2) - 24 = 2(y+4) 3x + 6 - 24 = 2y + 8 3x - 2y = 26 Plug x = -5y + 3 into 3x - 2y = 26 3(-5y + 3) - 2y = 26 -15y + 9 - 2y = 26 -17y = 17 y = -1 Plug y into x = -5y + 3 x = -5(-1) + 3 x = 8
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