Answer
$(-1,-2)$
Work Step by Step
$3x-4y=x-y+4$
$2x+6y=5y-4$
$2x=-y-4$
$x=\frac{-y-4}{2}$
$3(\frac{-y-4}{2})-4y=\frac{-y-4}{2}-y+4$
$\frac{-3y-4}{2}-4y=\frac{-y-4}{2}-y+4$
$\frac{-2y-8}{2}-3y=4$
$\frac{-2y-8}{2}-\frac{6y}{2}=4$
$\frac{-8y-8}{2}=4$
$-8y-8=8$
$-8y=16$
$y=-2$
$2x+6(-2)=5(-2)-4$
$2x-12=-10-4$
$2x=-2$
$x=-1$
$(-1,-2)$
