College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 5 - Systems of Equations and Inequalities - Exercise Set 5.1 - Page 527: 30

Answer

$(\frac{32}{7},-\frac{20}{7})$

Work Step by Step

$(5x=6y+40)$ $+$ $(2y=8-3x)$ $(5x-6y=40)$ $+$ $(3x+2y=8)$ $(15x-18y=120)$ $-$ $(15x+10y=40)$ $-28y=80$ $y=-\frac{20}{7}$ $5x=6y+40$ $5x=6(-\frac{20}{7})+40$ $5x=-\frac{120}{7}+40$ $5x=\frac{160}{7}$ $x=\frac{32}{7}$ $(\frac{32}{7},-\frac{20}{7})$
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